// Program takes a input a series of 
// integers prints a message indicating 
// whether it is even or odd
// Exercise 3.21 in D&D
#include<iostream.h>

// prototype for function that returns
// 1 if the input is even, 0 otherwise
int even(int numb);

main ()
{
  int int1;

  cout << "Enter an integer (or -999 if done): ";
  cin >> int1;
  while (int1 != -999)
    {
      if (even(int1) == 1)
	{
	  cout << int1
               << " is an even number\n";
	}
      else
	{ 
	  cout << int1 
	       << " is an odd number\n";
	}
      cout << "Enter an integer (or -999 if done): ";
      cin >> int1;
    }
  return 0;
}

// function takes an integer and returns
// 1 if the integer is even and 0 otherwise
int even(int numb)
  {
    if ((numb % 2) == 0)
      return 1;
    else
      return 0;
  }